Sixty thyristors rated 1.2 kV and 1 kA each are connected in series and parallel to form a 10 kV, 5.5 kA switch with 6 parallel paths. What is the efficiency of the switch?
Correct answer A. 76.3 %
Explanation
Six parallel paths of 60 devices give 10 in series. Efficiency = (10 kV × 5.5 kA)/(60 × 1.2 kV × 1 kA) = 55/72 ≈ 76.4%, matching about 76.3%.
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