A mass of 0.50 kg attached to a spring of spring constant 200 N/m oscillates horizontally. What is the period of oscillation?
Correct answer B. 0.31 s
Explanation
T = 2π√(m/k) = 2π√(0.50/200) = 2π × 0.050 ≈ 0.31 s. Forgetting the 2π factor gives 0.050 s, and inverting m/k gives a far larger value.
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