A gas in a cylinder at a constant pressure of 1.0 × 10⁵ Pa pushes a piston of area 0.020 m² outwards through 0.15 m. What work is done by the gas?
Correct answer D. 300 J
Explanation
Force = PA = 1.0 × 10⁵ × 0.020 = 2000 N, and W = Fd = 2000 × 0.15 = 300 J. Equivalently W = PΔV with ΔV = 3.0 × 10⁻³ m³.
Answer checked How we write and check questions
Discussion