Practice mode Thermodynamics

400 J of work is done on a gas while it gives out 150 J of heat. What is the change in its internal energy?

Correct answer D. +250 J

Explanation

With W as work done by the gas, W = −400 J and Q = −150 J. ΔU = Q − W = −150 + 400 = +250 J, so the internal energy rises.

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