How much work is needed to move a charge of 2.0 μC between two points whose potential difference is 150 V?
Correct answer D. 3.0 × 10⁻⁴ J
Explanation
W = qV = 2.0 × 10⁻⁶ × 150 = 3.0 × 10⁻⁴ J. Treating the charge as 2.0 C instead of 2.0 μC gives 3.0 × 10² J.
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