A capacitor holding 100 μC discharges through a resistor. Approximately what charge remains after a time equal to two time constants?
Correct answer D. 14 μC
Explanation
During discharge q = q₀e^(−t/RC). After t = 2RC, q = 100 × e⁻² ≈ 100 × 0.135 ≈ 14 μC. Halving the charge per time constant wrongly gives 25 μC.
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