Two silicon diodes (0.7 V each) are connected in series, both forward biased, with a 230 Ω resistor across a 3.0 V supply. What is the current?
Correct answer D. 7.0 mA
Explanation
Total diode drop = 2 × 0.7 = 1.4 V, so I = (3.0 − 1.4)/230 = 1.6/230 ≈ 7.0 × 10⁻³ A = 7.0 mA.
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