A loop of area 0.050 m² is in a uniform field of 0.40 T. The normal to the loop makes an angle of 60° with the field. What is the flux through the loop?
Correct answer C. 1.0 × 10⁻² Wb
Explanation
Φ = BA cos θ, where θ is the angle between B and the normal. Φ = 0.40 × 0.050 × cos 60° = 0.020 × 0.5 = 1.0 × 10⁻² Wb. Using sin 60° gives 1.7 × 10⁻² Wb.
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