Two identical cells, each of emf 1.5 V and internal resistance 0.50 Ω, are connected in series with a 2.0 Ω resistor. What current flows?
Correct answer C. 1.0 A
Explanation
In series, total emf = 3.0 V and total internal resistance = 1.0 Ω. Current I = 3.0/(2.0 + 1.0) = 1.0 A. Ignoring internal resistance gives 1.5 A.
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