A 20 Ω resistor carries a steady current of 0.30 A. What power is dissipated in it?
Correct answer D. 1.8 W
Explanation
Power P = I²R = (0.30 A)² × 20 Ω = 0.090 × 20 = 1.8 W. The value 6.0 W is the potential difference IR, not the power.
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