A sinusoidal voltage of peak value 100 V is applied across a 50 Ω resistor. What is the average power dissipated?
Correct answer D. 100 W
Explanation
P = V_rms²/R = (V₀²/2)/R = 100² ÷ (2 × 50) = 100 W. Using the peak voltage directly as V²/R gives 200 W.
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