A 0.50 H inductor of negligible resistance is connected to a 230 V, 50 Hz supply. What rms current flows?
Correct answer B. 1.5 A
Explanation
X_L = 2πfL = 2π × 50 × 0.50 = 157 Ω. I_rms = V/X_L = 230 ÷ 157 ≈ 1.5 A. Leaving out 2π gives X = 25 Ω and a current of 9.2 A.
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