What volume of hydrogen at STP is produced when 2.3 g of sodium reacts completely with excess water (Na = 23, molar volume = 22.4 dm³)?
Correct answer D. 1.12 dm³
Explanation
2Na + 2H₂O → 2NaOH + H₂. Moles of Na = 2.3/23 = 0.10 mol, giving 0.050 mol H₂. Volume = 0.050 × 22.4 = 1.12 dm³.
Answer checked How we write and check questions
Discussion