According to the Arrhenius equation, k = A e^(−Ea/RT), how does the rate constant change if a reaction has a larger activation energy at the same temperature?
Correct answer A. k becomes smaller
Explanation
A larger Ea makes the exponent −Ea/RT more negative, so e^(−Ea/RT) and hence k decrease. Reactions with high activation energies are slower at a given temperature.
Answer checked How we write and check questions
Discussion