What pressure is exerted by 0.50 mol of an ideal gas in a 10 dm³ vessel at 27 °C (R = 0.0821 dm³ atm K⁻¹ mol⁻¹)?
Correct answer D. 1.23 atm
Explanation
P = nRT/V = 0.50 × 0.0821 × 300 K ÷ 10 dm³ = 1.23 atm. Using 27 instead of 300 K gives 0.111 atm.
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