How many moles of gas occupy 4.1 dm³ at 2.0 atm and 400 K (R = 0.0821 dm³ atm K⁻¹ mol⁻¹)?
Correct answer B. 0.25 mol
Explanation
n = PV/RT = (2.0 × 4.1) ÷ (0.0821 × 400) = 8.2 ÷ 32.8 = 0.25 mol. The units of R require pressure in atm and volume in dm³.
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