Ethoxyethane (C₂H₅OC₂H₅) and 1-methoxypropane (CH₃OC₃H₇) illustrate ____.
Correct answer D. metamerism
Explanation
Both are ethers of formula C₄H₁₀O, but the alkyl groups on either side of the oxygen differ. This type of isomerism, with unequal distribution of carbon around a polyvalent functional group, is called metamerism.
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