Using E°(Fe²⁺/Fe) = −0.44 V and E°(Cu²⁺/Cu) = +0.34 V, which reaction is spontaneous under standard conditions?
Correct answer B. Fe + Cu²⁺ → Fe²⁺ + Cu
Explanation
Iron has the more negative potential, so it is oxidised and reduces Cu²⁺. E°cell = 0.34 − (−0.44) = +0.78 V, which is positive.
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