In Cl₂ + 2NaOH → NaCl + NaOCl + H₂O, how do the oxidation numbers of chlorine change?
Correct answer C. From 0 to −1 and from 0 to +1
Explanation
Chlorine is 0 in Cl₂, −1 in NaCl and +1 in NaOCl. The same element is both reduced and oxidised, so this is a disproportionation reaction.
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