For which equilibrium is Kp equal to Kc at any temperature?
Correct answer B. H₂(g) + I₂(g) ⇌ 2HI(g)
Explanation
Kp = Kc(RT)^Δn, where Δn is the change in moles of gas. For the HI equilibrium Δn = 2 − 2 = 0, so (RT)⁰ = 1 and Kp = Kc.
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