Why is the H–F bond much stronger than the H–I bond?
Correct answer C. H–F is shorter and more polar, so the attraction between atoms is greater
Topic / 39 questions
Chemical Bonding MCQs are multiple-choice questions on how atoms join to form molecules, covering VSEPR theory, hybridisation, sigma and pi bonds, dipole moment, polarity and bond energy. They follow the MDCAT chemistry curriculum, and every question on MCQs360 shows its correct answer instantly so you can check shapes and bond counts as you practise.
Correct answer C. H–F is shorter and more polar, so the attraction between atoms is greater
Correct answer D. 4.8 D
Correct answer D. CHCl₃
Correct answer D. In NH₃ the lone pair moment adds to the bond moments, while in NF₃ it opposes them
Correct answer D. 12 sigma and 3 pi
Correct answer A. By head-on (end-to-end) overlap of orbitals along the internuclear axis
Correct answer D. Lone pair–lone pair > lone pair–bond pair > bond pair–bond pair
Correct answer B. Tetrahedral, 109.5°
Correct answer C. Bent (angular)
Correct answer B. Trigonal planar
Correct answer A. Tetrahedral
Correct answer D. sp
Correct answer B. sp³
Correct answer A. 33.3%
Correct answer A. C≡C > C=C > C–C
Correct answer D. Trigonal pyramidal
Correct answer A. BeCl₂
Correct answer C. sp²
Correct answer C. 416 kJ mol⁻¹
Correct answer B. H–F
Shape questions ask you to apply VSEPR theory and hybridisation to molecules such as NH₃, H₂O, BF₃, PCl₅ and SF₆, giving the shape, bond angle and hybridisation of the central atom. Carbon hybridisation in compounds and allotropes such as graphite also appears, along with counting sigma and pi bonds in ethene, ethyne and carbon dioxide. Other questions cover how sigma and pi bonds form, bond energy and bond strength, the order of single, double and triple bond energies, and average bond energies from atomisation data. Dipole moment questions test its unit, the debye, molecular polarity and calculating percentage ionic character from observed and theoretical dipole moments.
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The PMDC MDCAT curriculum for Chemical Bonding covers VSEPR theory and the shapes of molecules, sigma and pi bonds, hybridisation, dipole moment, molecular polarity and ionic character, and bond energy and bond strength. Shapes and hybridisation of common molecules are the most frequently tested parts.
Chemical bonding is one of the most tested chemistry topics in MDCAT, ECAT, NUMS and AKU entry tests and FSc board papers in Pakistan. It is also a core chapter for NEET and JEE Main in India and HSC and medical admission tests in Bangladesh.
Carbon dioxide is linear, so its two C=O bond dipoles are equal in size and point in opposite directions. They cancel each other out, giving the molecule a net dipole moment of zero even though each bond is polar.
Last reviewed October 2026