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Chemical Bonding MCQs

Chemical Bonding MCQs are multiple-choice questions on how atoms join to form molecules, covering VSEPR theory, hybridisation, sigma and pi bonds, dipole moment, polarity and bond energy. They follow the MDCAT chemistry curriculum, and every question on MCQs360 shows its correct answer instantly so you can check shapes and bond counts as you practise.

Question 01 Chemical Bonding

Why is the H–F bond much stronger than the H–I bond?

Correct answer C. H–F is shorter and more polar, so the attraction between atoms is greater

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Question 06 Chemical Bonding

How is a sigma (σ) bond formed?

Correct answer A. By head-on (end-to-end) overlap of orbitals along the internuclear axis

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Question 07 Chemical Bonding

According to VSEPR theory, which order of electron-pair repulsion is correct?

Correct answer D. Lone pair–lone pair > lone pair–bond pair > bond pair–bond pair

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About Chemical Bonding MCQs

Shape questions ask you to apply VSEPR theory and hybridisation to molecules such as NH₃, H₂O, BF₃, PCl₅ and SF₆, giving the shape, bond angle and hybridisation of the central atom. Carbon hybridisation in compounds and allotropes such as graphite also appears, along with counting sigma and pi bonds in ethene, ethyne and carbon dioxide. Other questions cover how sigma and pi bonds form, bond energy and bond strength, the order of single, double and triple bond energies, and average bond energies from atomisation data. Dipole moment questions test its unit, the debye, molecular polarity and calculating percentage ionic character from observed and theoretical dipole moments.

Key facts to remember

  • VSEPR theory: electron pairs around a central atom repel one another, with lone pair–lone pair > lone pair–bond pair > bond pair–bond pair repulsion.
  • NH₃ is trigonal pyramidal (about 107°) and H₂O is bent (about 104.5°); both have an sp³ hybridised central atom.
  • sp, sp² and sp³ hybridisation give linear (180°), trigonal planar (120°) and tetrahedral (109.5°) arrangements; PCl₅ (sp³d) is trigonal bipyramidal and SF₆ (sp³d²) is octahedral.
  • A sigma bond forms by head-on overlap of orbitals and a pi bond by sideways overlap of parallel p orbitals; a double bond is one σ and one π, and a triple bond is one σ and two π.
  • Dipole moment μ = q × d and is measured in debye, where 1 D = 3.34 × 10⁻³⁰ C m.
  • Carbon–carbon bond energy increases in the order C–C < C=C < C≡C.

Exams that include Chemical Bonding MCQs

Pakistan

  • MDCAT
  • ECAT
  • NUMS
  • AKU
  • FSc boards

India

  • NEET
  • JEE Main

Bangladesh

  • HSC
  • Medical Admission Test

How to prepare for Chemical Bonding MCQs

  1. Count bond pairs and lone pairs around the central atom first, then name the shape and hybridisation.
  2. Learn a short table of shapes from AB₂ to AB₆, including the lone-pair versions such as AB₃E and AB₂E₂.
  3. To count sigma and pi bonds, remember every single bond is σ and each extra bond in a double or triple bond is π.
  4. Revise how symmetry cancels bond dipoles, which explains why CO₂ and BF₃ are non-polar.

Frequently asked questions

What does the MDCAT syllabus include in Chemical Bonding?

The PMDC MDCAT curriculum for Chemical Bonding covers VSEPR theory and the shapes of molecules, sigma and pi bonds, hybridisation, dipole moment, molecular polarity and ionic character, and bond energy and bond strength. Shapes and hybridisation of common molecules are the most frequently tested parts.

Which exams ask Chemical Bonding MCQs?

Chemical bonding is one of the most tested chemistry topics in MDCAT, ECAT, NUMS and AKU entry tests and FSc board papers in Pakistan. It is also a core chapter for NEET and JEE Main in India and HSC and medical admission tests in Bangladesh.

Why is CO₂ non-polar although its C=O bonds are polar?

Carbon dioxide is linear, so its two C=O bond dipoles are equal in size and point in opposite directions. They cancel each other out, giving the molecule a net dipole moment of zero even though each bond is polar.

Last reviewed October 2026