What is the percentage by mass of carbon in ethanoic acid, CH₃COOH (C = 12, H = 1, O = 16)?
Correct answer A. 40%
Explanation
Molar mass of CH₃COOH = 24 + 4 + 32 = 60 g mol⁻¹. Percentage of carbon = (24 ÷ 60) × 100 = 40%.
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