How much energy is emitted when the electron of a hydrogen atom falls from n = 2 to n = 1 (Eₙ = −13.6/n² eV)?
Correct answer B. 10.2 eV
Explanation
E₂ = −3.4 eV and E₁ = −13.6 eV, so the energy emitted is −3.4 − (−13.6) = 10.2 eV, giving the first Lyman line.
Answer checked How we write and check questions
Discussion