What is the approximate percentage by mass of bromine in bromoethane, C₂H₅Br (C = 12, H = 1, Br = 80)?
Correct answer C. 73.4%
Explanation
Molar mass of C₂H₅Br = 24 + 5 + 80 = 109 g mol⁻¹. Percentage of Br = (80 ÷ 109) × 100 ≈ 73.4%.
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