An alkyl halide reacts with OH⁻ by the SN2 mechanism. If is doubled and is tripled, the rate becomes ____.
Correct answer B. 6 times the original
Explanation
For SN2, rate = k[RX][OH⁻]. Both reactants appear to the first power, so doubling [RX] and tripling [OH⁻] multiplies the rate by 2 × 3 = 6, making it 6 times the original.
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