Take C = 12, H = 1, I = 127. What mass of triiodomethane, CHI₃, can form from 0.10 mol of propanone in the iodoform reaction?
Correct answer D. 39.4 g
Explanation
Each CH₃CO– group gives one CHI₃. M(CHI₃) = 12 + 1 + 3 × 127 = 394 g/mol, so 0.10 mol gives 0.10 × 394 = 39.4 g. The value 38.1 g ignores carbon and hydrogen.
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