Take Ag = 108. What mass of silver is deposited when 0.10 mol of ethanal reacts completely with Tollens’ reagent?
Correct answer C. 21.6 g
Explanation
Each aldehyde group reduces two Ag⁺ ions: RCHO + 2Ag⁺ → RCOOH + 2Ag (in alkaline conditions). So 0.10 mol ethanal gives 0.20 mol Ag, and mass = 0.20 × 108 = 21.6 g.
Answer checked How we write and check questions
Discussion