What mass of ethanol can be obtained from the complete fermentation of 90 g of glucose (M = 180 g/mol, ethanol M = 46 g/mol)?
Correct answer A. 46 g
Explanation
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂. Moles of glucose = 90/180 = 0.50 mol, giving 1.0 mol ethanol. Mass = 1.0 × 46 = 46 g. Forgetting the 1:2 ratio gives 23 g.
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