6.0 g of ethanoic acid reacts with excess ethanol and gives 5.28 g of ethyl ethanoate. What is the percentage yield (CH₃COOH = 60, CH₃COOC₂H₅ = 88)?
Correct answer A. 60%
Explanation
0.1 mol acid gives a theoretical 0.1 mol, i.e. 8.8 g of ester. Percentage yield = (5.28 ÷ 8.8) × 100 = 60%.
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