Practice mode / Problems on H.C.F and L.C.M Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. A Option A: 4 B Option B: 7 C Option C: 9 D Option D: 13 Correct answer A. 4 Show answer Report a problem How we write and check questions
Question 01 / Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to: A Option A: 55/601 B Option B: 601/55 C Option C: 11/120 D Option D: 120/11 Correct answer C. 11/120 Show answer Open question
Question 02 / Problems on H.C.F and L.C.M The H.C.F. of 9/10, 12/25, 18/35 and 21/40 is: A Option A: 3/5 B Option B: 252/5 C Option C: 3/1400 D Option D: 63/700 Correct answer C. 3/1400 Show answer Open question
Question 03 / Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2: 3. Then sum of the number is: A Option A: 28 B Option B: 32 C Option C: 40 D Option D: 64 Correct answer C. 40 Show answer Open question
Question 04 / Problems on H.C.F and L.C.M Which of the following has the most number of divisors? A Option A: 99 B Option B: 101 C Option C: 176 D Option D: 182 Correct answer C. 176 Show answer Open question
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