Practice mode / Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: A Option A: 2 x 2 x 3 x 3 x 7 B Option B: 2 x 2 x 2 x 3 x 7 C Option C: 3 x 3 x 3 x 3 x 7 D Option D: 2 x 3 x 3 x 3 x 7 Correct answer A. 2 x 2 x 3 x 3 x 7 Show answer Report a problem How we write and check questions
Question 01 / Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is: A Option A: 1008 B Option B: 1015 C Option C: 1022 D Option D: 1032 Correct answer B. 1015 Show answer Open question
Question 02 / Problems on H.C.F and L.C.M The ratio of two numbers is 3: 4 and their H.C.F. is 4. Their L.C.M. is: A Option A: 12 B Option B: 16 C Option C: 24 D Option D: 48 Correct answer D. 48 Show answer Open question
Question 03 / Problems on H.C.F and L.C.M What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30? A Option A: 196 B Option B: 630 C Option C: 1260 D Option D: 2520 Correct answer B. 630 Show answer Open question
Question 04 / Problems on H.C.F and L.C.M The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: A Option A: 279 B Option B: 283 C Option C: 308 D Option D: 318 Correct answer C. 308 Show answer Open question
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