At a certain time of day the angle of elevation of the sun is 30°. A building on level ground casts a shadow 45 m long at that time. Taking √3 = 1.732, what is the height of the building?
Correct answer C. 25.98 m
Explanation
In the right triangle, tan 30° = h / 45, so h = 45/√3 = 15√3 = 15 x 1.732 = 25.98 m.
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