From the top of a vertical cliff 90 m high, the angle of depression of a boat on the sea is 30°. Taking √3 = 1.732, how far is the boat from the foot of the cliff?
Correct answer C. 155.88 m
Explanation
The angle of depression equals the angle of elevation from the boat, so tan 30° = 90 / d and d = 90√3 = 155.88 m.
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