For rate = k, the rate is 6.0 × 10⁻³ mol dm⁻³ s⁻¹ when = 0.10 and = 0.20 mol dm⁻³. What is k?
Correct answer A. 0.30 dm³ mol⁻¹ s⁻¹
Explanation
k = rate ÷ ([A][B]) = 6.0 × 10⁻³ ÷ (0.10 × 0.20) = 0.30 dm³ mol⁻¹ s⁻¹ for this second-order reaction.
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